How to access WCC server using Python ?

How to access WCC server using Python ?

How to login to web site using Python ?

Source code : https://github.com/sterin501/PythonScripts/blob/master/ucm/ucmlogin.py

Main Tasks

1. Getting login URL and parameters

2. Creat phyton file

3. Running phyton code

WCC server ->ucm.company.com:16200

1.1 Access UCM URL in chrome

http://ucm.company.com:16200/cs/

click on login

http://ucm.company.com:16200/cs/login/login.htm

1.2 Cltr+Shift+I ( Developer mode )

Click on Network

1.3 Enter username and password , then enter

1.4 Select j_security_check (status 302)

1.5 Click on Header

Here , http://ucm.company.com:16200/cs/login/j_security_check

IS Authentication URL and , other parameters will be 

displayed

if you select other (302 status) URL ,

http://ucm.company.com:16200/adfAuthentication?login=true ,

Which means , login is already done .

1.6 :

This means

LOGIN_URL = "http://ucm.company.com:16200/cs/login/j_security_check”

j_username=weblogic

j_password= welcome1

2. Creat phyton file

2.1, For testing we will access , content belongs

to secure group

URL to Access : http://ucm.company.com:16200/cs/idcplg?IdcService=DOC_INFO&dID=414&dDocName=AWSECM000414&IsSoap=1

2.2 Script :

#!/bin/python

import requests

import re

from lxml import html

USERNAME = "weblogic"

PASSWORD = "welcome1"

IdcService=DOC_INFO&dID=3223&dDocName=STJACOBPC1IDCO003622&IsSoap=1"

LOGIN_URL = 

"http://ucm.company.com:16200/cs/login/j_security_check"

URL = "http://ucm.company.com:16200/cs/idcplg?

IdcService=DOC_INFO&dID=414&dDocName=AWSECM000414&IsSoap=1 "

session_requests = requests.session()

# Get login csrf token

result = session_requests.get(LOGIN_URL)

# Create payload

payload = {

"j_username": USERNAME,

"j_password": PASSWORD,

}

flag = 0

# Perform login

result = session_requests.post(LOGIN_URL, data = payload, headers = dict(referer = LOGIN_URL))

regex = 'idcToken = ".{13,47}"'

pattern = re.compile(regex)

for line in result:

 role = re.findall(pattern,line)

 if role:

  print line

  flag=1

if (flag==1):

 result = session_requests.get(URL, headers = dict(referer = URL))

 for line in result:

 print(line)

else:

print("In Valid Login")

result = session_requests.get(LOGIN_URL)

This will perform ,login part

with layload

regex = 'idcToken = ".{13,47}"'

Will check for correct login .

result = session_requests.get(URL, headers = dict(referer = URL))

This will use to access the content info page URL

3. Running phyton code

./ucmlogin.py

Correct login : , after getting idctoken, it will print content info

var idcToken = "1471027281668:4F907EFE0CE5AFE561EDCA60CF8cB71E2";

// user specific strings and flags: used only to d

<?xml version='1.0' encoding='utf-8' ?>

SOAP-ENV:Envelope xmlns:SOAP-

ENV="http://schemas.xmlsoap.org/soap/envelope/">

<SOAP-E

NV:Body>

<idc:service mlns:idc="http://www.stellent.com/IdcService/" IdcService="DOC_INFO">

<idc:document dDocName="AWSECM000

414" dStatus="RELEASED" dDocTitle="Test RIDC 

Checkin" 

DocUrl="http://localhost:16200/cs/groups/secure/docum

ents/document/zwnt/md

aw/~edisp/awsecm000414.txt" dUser="weblogic" 

dDocFormats="text/plain" dID="414">

In correct Login , There wont be any idctoken

./ucmlogin.py

In Valid Login